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Wild ownz al

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A truck crossing the prairies at constant speed of 110km per hour gets 8km per litre of gas. Gas costs 0.68 dollars per litre.

The truck loses 0.10 km per litre in fuel efficiency for each km per hour increase in speed.

Drivers are paid 35 dollars per hour in wages benefits.

Fixed costs for running the truck are 15.50 dollars per hour.

If a trip of 450km is planned, what speed will minimize operating expenses?

This is the formula I made:

C = Cost of operation

v = increases of speed (1km/h)

C(v) = 0.68(450/(8 - v/10)) + (450/(110+v))(35+15.5)

The truck loses 0.10 km per litre in fuel efficiency for each km per hour increase in speed.

Drivers are paid 35 dollars per hour in wages benefits.

Fixed costs for running the truck are 15.50 dollars per hour.

If a trip of 450km is planned, what speed will minimize operating expenses?

This is the formula I made:

C = Cost of operation

v = increases of speed (1km/h)

C(v) = 0.68(450/(8 - v/10)) + (450/(110+v))(35+15.5)

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