Optimizing Boat Frequency: Eastward vs. Westward Waves

  • Thread starter Thread starter FelicitaH
  • Start date Start date
  • Tags Tags
    Frequency Waves
AI Thread Summary
The discussion centers on calculating wave frequency as a boat moves westward against eastward-traveling waves. The correct approach involves recognizing that the boat's movement towards the waves increases the frequency of wave impacts. Initially, the user incorrectly subtracted the boat's speed from the wave speed, leading to an incorrect frequency calculation. The correct calculation involves adding the speeds, resulting in a frequency of approximately 0.208 Hz. The confusion stems from a misunderstanding of wave interactions, but the final conclusion clarifies that the boat experiences waves more frequently when moving towards them.
FelicitaH
Messages
9
Reaction score
0
There are two parts to this question. I got the first part and thought the second would be relatively easy to answer, but I keep getting it wrong:

Ocean waves are traveling to the east at 3.2 m/s with a distance of 22m between crests.

a) With what frequency do the waves hit the front of the boat when the boat is at anchor? ** 3.2/22=.1455 Hz, which I got right.

b) With what frequency do the waves hit the front of a boat when the boat is moving westward at 1.4m/s?

Now, b/c they are moving towards each other, I substrated 1.4 from 3.2 and I got 1.8. I then got 1.8/22=0.0818, which is incorrect.

What am I doing wrong with regard to the second part?
 
Physics news on Phys.org
If you are walking towards a wave, will the wave hit you more frequently or less frequently? Will it seem like the wave is moving faster or slower?

Similarly, will a boat moving towards the wave be hit with a higher or lower frequency than it would were it at rest?

Ask yourself these questions, and you will see if you did something incorrectly.
 
Ok. It would be hit at a greater frequency, so I should add instead of substracting?

That confuses me... because I thought that if two waves were moving toward each other it was destructive (or something like that) and so you would subtract from one another. At least, that's how I understood what my prof was saying.
 
FelicitaH said:
That confuses me... because I thought that if two waves were moving toward each other it was destructive (or something like that) and so you would subtract from one another. At least, that's how I understood what my prof was saying.
But is the boat a wave?

When two waves collide, they can cancel each other out if their characteristics meet certain requirements. You understood your professor correctly.

(Disclaimer: It turns out that the boat (and all matter) has a wave component given by one of de Broglie's equations. But you don't need to worry about that, as it is a negligible component.)
 
I just assumed I could consider the boat a wave. Not sure why.

So -- 1.4 + 3.2 = 4.6/22 = .2091

Is that correct then? I only have one more chance to answer this question correctly, which I why I'd just like to make sure, if that's possible.

*EDIT* Actually, that's wrong. That was an answer that I tried earlier...
 
Last edited:
The logic is sound, and the math appears correct. The question is - do you think it is the right answer?
 
Yeah, it's not right. I tried that answer earlier. Apparently it's too small.
 
my approach is nothing different than what has been done before, but assume the boat is at a point B 22 m eastwards of point A where the first wave is approaching.

When the wave collides the boat they both have traveled a distance total of 22 m, thus:

3.2\cdot t + 1.4 \cdot t = 4.6\cdot t = 22 \Rightarrow t = 4.8 s

Then the next wave is again at a distance 22 m and collides after 4.8 seconds.

--> thus the frequency = 1/4.8 = 0.208 Hz
 

Similar threads

Replies
3
Views
11K
Replies
5
Views
6K
Replies
4
Views
3K
Replies
1
Views
9K
Replies
29
Views
2K
Replies
5
Views
2K
Replies
7
Views
3K
Back
Top