Optimizing Lever Mechanics for Lifting Heavy Objects

AI Thread Summary
To lift a 2500kg boulder using a lever, the boy must balance the torques around the fulcrum. The lever's length from the fulcrum to the boulder is 0.6 meters, and the boy's weight is 50kg. By setting the boy's torque equal to the boulder's torque, the calculation shows that the required length of the lever on the boy's side is 30 meters. This conclusion aligns with the principles of levers and torque, confirming the solution's validity. The discussion emphasizes the importance of understanding lever mechanics for lifting heavy objects.
Kogsug
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I can't figure this problem out and i don't know where to start.

A young boy(50kg) wants to lift a boulder with a mass of 2500kg. He can wedge a board under it so that from the boulder to a pivot/fulcrum is 0.6 meters. How long does the other end of the board have to be for the boy to lift the boulder.

Any ideas?
 
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What principles apply here? (See, this is why you should use the Homework Posting Template that is provided when you start a new homework thread. It should not be considered optional.)

Tell us what you know about levers and fulcrums and maybe even torques. You must show us your work in order to get our help (PF rules).
 
you know your origin, right?
does it make sense that if you set the persons torque equal to the boulder's torque you would be able to solve this problem?
 
what do u mean what principles apply here? this is the full problem word for word. we just started levers... and we have not done torgue.

does this work?

(B)(x)=(0.6m)(load)

(50kg)(x)=(0.6m)(2500kg)

x={(0.6m)(2500kg)}/(50kg)

so x=30 meters?

can somone please tell me if this is right?
 
Last edited:
Looks good to me.
 
ok then... thank you
 
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