Optimizing Thrown Ball Trajectories

AI Thread Summary
The discussion focuses on optimizing the thrown ball trajectory, specifically determining the angle and speed for maximum range. The optimal angle for maximum distance is identified as 45 degrees, with a required speed of 9.3 m/s to achieve a range of 9 m on Earth. When considering a planet with a gravitational acceleration of 22 m/s², the astronaut can throw the ball approximately 4.009 m. The participant struggles with calculating the maximum height reached on this planet, indicating confusion over the correct use of vertical acceleration in their calculations. The thread highlights the importance of using accurate values in equations to solve for maximum height effectively.
Bryon
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Homework Statement



An astronaut in his space suit can throw a ball a maximum distance dmax = 9 m on the surface of the earth.

For a given speed of the ball, what angle to the horizontal q (in degrees) will yield the greatest range? 45 degrees

If the ball is thrown at this same angle q, what speed will produce this greatest range (9 m) ? 9.3m/s

How far can he throw the ball on a planet where g1 = 22 m/s2? 4.009

What height will the ball reach on this "maximum range" trajectory? (on the planet where g1 = 22 m/s2)? I am having a problem with this one. I need help!


Homework Equations



v(y) = v(initial)*sin(angle)
v(y) = v( y initial) + at
y = y(initial) + 0.5(v(inital) + v)t


The Attempt at a Solution



v(y) = 9sin(45) = 6.57

0 = 6.57 + 22(t)
t = 0.298

y = 0 + 0.5(6.57 + 0)*(0.298)
y = 0.978

Where did I go wrong? Did I need the vertial acceleration?

thanks!
 
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(y) = 9sin(45) = 6.57
It should be
(y) = 9.3sin(45)
 
Ah yes I made a type, it should be 9.3. But I still am having trouble finding the maximum height...It seems that every approach I've tried it comes up wrong.
 
Bryon said:
Ah yes I made a type, it should be 9.3. But I still am having trouble finding the maximum height...It seems that every approach I've tried it comes up wrong.
t = 0.2986
= 0.299
 
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