hutchphd
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You wouldn't know a short fellow called Tom Sawyer would you ?...jbriggs444 said:If I were less lazy,
Anyhow I took what @DrStupid did and made a little graph which I find useful. First I will choose some natural units ##r_0,g_0, m=1## to write the effective potential$$V_{eff}(r)=\frac 1 {2r^2}-\frac 1 r -a(r-1)$$ where I have changed the zero for the "added" radial potential . The graph and a "blown up" version near the minimum show the potential for various values of a. I think it comports with all the analyses.
I need pictures.