# Orbital period of a planet

1. Sep 29, 2010

### leonne

1. The problem statement, all variables and given/known data
We will compute the orbit of Eris, the infamous \tenth planet" that caused Pluto
to be demoted to \dwarf planet" status. Eris (also called 2003 UB313 in the
textbook) has a semimajor axis a = 68:048 AU and eccentricity e = 0:4336 based
on the best current observations. Calculate the orbital period P of Eris (in years).

2. Relevant equations
P^2=4pie^2)/G(m1+m2)) (a1+a2)^3

3. The attempt at a solution
would i just use this formula? I know it would work but not sure if i am suppose to use something else cause i was given eccentricity, but could not find any formula that uses it to find orbital period

2. Oct 1, 2010

### zhermes

The period does not depend on the eccentricity (kepler's third law).

3. Oct 1, 2010

### leonne

yea i figured that out thxs, eccentricity was for the other part of the problem

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