Orbital Potential Energy to find r and phi in terms of t.

AI Thread Summary
The discussion focuses on deriving the expressions for r and φ in terms of time t for a particle in a central force field with an orbit described by r=cφ^2. The potential energy is calculated as U=-l^2/mu (2c/r^3+l/2r^2), where l is angular momentum and mu is the reduced mass. A key equation, l=mu r^2 dφ/dt, is highlighted for integration to find r^2(t)=lt/mu. Participants suggest using dφ/dt to find dt/dφ and subsequently integrate to obtain the desired expressions for r and φ. The conversation emphasizes the importance of integration techniques in solving the problem.
10Exahertz
Messages
9
Reaction score
0

Homework Statement


A particle in central force field has the orbit r=cφ^2, c is a constant. Find the potential energy, Find r and phi in terms of t.
I get how to find the potential energy and found it to be U=-l^2/mu (2c/r^3+l/2r^2)
l is angular momentum and mu is the reduced mass
But how do I get r and phi in terms of t after this?

Homework Equations


From what my professor showed in class l=mu r^2 dφ/dt was important
he used that to integrate and get r^2(t)=lt/mu
I'm trying to use this method to get r and phi

Any help is much appreciated, thanks!
 
Physics news on Phys.org
10Exahertz said:
I'm trying to use this method to get r and phi
Sounds good. Once you have dφ/dt, you can get dt/dφ and integrate.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top