- #1
debrox
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Hi. I'm reading a differential equation book to prime myself best for my signals and systems class I'm in, and I've ran into some confusion.
If I had a differential equation like so:
y'(t) + \int y(t)dt = f(t) (1)
What would you say the order is? The definition says "the order of a differential equation is the highest derivative that appears in the equation."
Would I say it's a second order differential equation because:
h(t) = \int y(t)dt (2)
meaning:
h''(t) = y'(t) (3)
and substituting (2) and (3) into (1):
h''(t) + h(t) = f(t) (4)
If asked to solve such a differential equation, would I first solve (4) and then differentiate h(t) to find y(t), the original function of t in question?
If I had a differential equation like so:
y'(t) + \int y(t)dt = f(t) (1)
What would you say the order is? The definition says "the order of a differential equation is the highest derivative that appears in the equation."
Would I say it's a second order differential equation because:
h(t) = \int y(t)dt (2)
meaning:
h''(t) = y'(t) (3)
and substituting (2) and (3) into (1):
h''(t) + h(t) = f(t) (4)
If asked to solve such a differential equation, would I first solve (4) and then differentiate h(t) to find y(t), the original function of t in question?
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