Order of convergence of sequence

[Damidami]

Homework Statement

I have to find the order of convergence of the following sequence

b_n = \left( \frac{5}{6} \right)^{n^2}

I have numerically tested that it has to be a real number between 1 and 2, but I can't find it exactly.


I also have this doubt: does every sequence have an order of convergence? (a real number p such that | b_{n+1}/b_{n}^p| converges to a non-zero constant )

Homework Equations

The Attempt at a Solution

Here http://translate.google.com/translate?hl=es&sl=es&tl=en&u=http%3A%2F%2Festudiandoenexactas.wordpress.com%2F2011%2F08%2F29%2Ftp-1-ej-1-3%2F" are my futile attempts at solving it.

 

[grief]

It seems to me that there is no order of convergence in this case, according to the definition you gave. Try to plug the formula into the definition of order of convergence.

\frac{5}{6}^{{(n+1)}^2} / {(\frac{5}{6}^{n^2})}^p = \frac{5}{6}^{{(n+1)}^2-pn^2}. If p<=1, then the exponent tends to infinity, so the whole expression tends to 0. If p>1, then the exponent tends to -infinity and the whole expression tends to infinity.