Organic chemistry acetal reaction help

AI Thread Summary
The discussion revolves around the acetal formation process, specifically involving cyclohexanol and carbonyl groups. Participants clarify that to create an acetal, one needs alcohols, a leaving group like water, and an acid catalyst. The conversation highlights the importance of understanding the hemiacetal intermediate, which is formed before the final acetal product. There is also a focus on the functionalities required for the reaction and the steps leading to the final product. Overall, the thread emphasizes the key components and mechanisms involved in acetal formation in organic chemistry.
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<Moderator's note: Moved from a technical forum and thus no template.>

OChem Question:
o7XLLLJ.jpg
My Answer:

upload_2017-10-2_16-43-9.png


Not sure if this is correct. Anyone?
 

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What's your reasoning for the cyclohexanol hosting an acetal carbon?

Edit: is this homework? If so, it belongs in the homework forums.
 
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TeethWhitener said:
What's your reasoning for the cyclohexanol hosting an acetal carbon?

Edit: is this homework? If so, it belongs in the homework forums.

Cyclohexanol is larger. I think it could go either way. Are there major and minor products here? Sorry I thought this was the homework forum. How do I move this thread?
 
I asked the mods to migrate the thread. Meanwhile, can you tell me how to make an acetal? What functional groups are required?
 
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TeethWhitener said:
I asked the mods to migrate the thread. Meanwhile, can you tell me how to make an acetal? What functional groups are required?

Thank you so much. You need alcohols, a leaving group (like H2O) and acid catalyst to make an acetal.
 
IntegralDerivative said:
Thank you so much. You need alcohols, a leaving group (like H2O) and acid catalyst to make an acetal.
Alcohol and? What other organic functionality do you need?
 
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TeethWhitener said:
Alcohol and? What other organic functionality do you need?

Carbonyl group?
 
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Yes. If you have a carbonyl group, what happens if you add one equivalent of alcohol? (Formally, ignoring equilibrium considerations) Do you get an acetal right off the bat?
 
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TeethWhitener said:
Yes. If you have a carbonyl group, what happens if you add one equivalent of alcohol? (Formally, ignoring equilibrium considerations) Do you get an acetal right off the bat?

You will get a hemiacetal. But I thought you need oxidizing agents to turn alcohols into carbonyls? How do we get a carbonyl in this case with only sulfuric acid?
 
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  • #10
IntegralDerivative said:
You will get a hemiacetal. But I thought you need oxidizing agents to turn alcohols into carbonyls? How do we get a carbonyl in this case with only sulfuric acid?
You're getting ahead of yourself. Look at your original problem and tell me what functionalities you have.
Edit: hemiacetal is right (and is the important part). The rest of the post veers off the path a little.
 
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  • #11
TeethWhitener said:
You're getting ahead of yourself. Look at your original problem and tell me what functionalities you have.
Edit: hemiacetal is right (and is the important part). The rest of the post veers off the path a little.

I see. So the hemiacetal is the
upload_2017-10-2_17-44-23.png
. and so it will form a carbonyl after the H2O group leaves and then the cyclohexanol will attack to the carbonyl carbon?

Do you know how to name the
upload_2017-10-2_17-44-23.png
molecule?
 
  • #12
IntegralDerivative said:
I see. So the hemiacetal is the View attachment 212179 . and so it will form a carbonyl after the H2O group leaves and then the cyclohexanol will attack to the carbonyl carbon?

Do you know how to name the View attachment 212179 molecule?
You've added a step. "Hemiacetal" literally means "half an acetal." Meaning you're already halfway to an acetal. Take another stab at it.
 
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  • #13
TeethWhitener said:
You've added a step. "Hemiacetal" literally means "half an acetal." Meaning you're already halfway to an acetal. Take another stab at it.
I am not sure what you mean. I described these steps here I think:

upload_2017-10-2_17-51-52.png
 
  • #14
IntegralDerivative said:
I am not sure what you mean. I described these steps here I think:

View attachment 212181
Ah I see what you're saying. That's an oxonium, not a carbonyl. Yes, these are the steps you want. So what's your final product?
 
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  • #15
TeethWhitener said:
Ah I see what you're saying. That's an oxonium, not a carbonyl. Yes, these are the steps you want. So what's your final product?

This:
upload_2017-10-2_17-59-22.png
 
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  • #16
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  • #17
TeethWhitener said:
Good work.

Thank you so much!
 

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