Organic Chemistry - Alcohol Synthesis Problem

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SUMMARY

The discussion focuses on synthesizing alcohol from an alkyne using hydration reactions and specific reagents. The suggested method involves converting the alkyne to an alkene using sodium in liquid ammonia, followed by bromination with N-Bromosuccinimide (NBS) to produce allyl bromide. The reaction with aqueous sodium hydroxide yields the desired alcohol, which can then undergo acidic hydrolysis to form 1,3-butanediol. Key corrections were made regarding the structure of the alkyne and the reaction pathway.

PREREQUISITES
  • Understanding of organic chemistry principles, specifically hydration reactions.
  • Familiarity with alkyne and alkene structures and their hybridization.
  • Knowledge of reagents such as N-Bromosuccinimide (NBS) and sodium in liquid ammonia.
  • Experience with substitution reactions and acidic hydrolysis in organic synthesis.
NEXT STEPS
  • Research the mechanism of hydration reactions involving alkynes and alkenes.
  • Learn about the use of N-Bromosuccinimide (NBS) in organic synthesis.
  • Study the process of acidic hydrolysis and its applications in alcohol synthesis.
  • Explore the synthesis of 1,3-butanediol and its industrial applications.
USEFUL FOR

Organic chemists, students studying organic synthesis, and anyone involved in alcohol production from alkynes will benefit from this discussion.

tsaitea
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I have attached a file of the alcohol I need to synthesize and my futile attempt... I was thinking of using a hydration reaction to make the alcohol from the alkyne group. So basically I would mix the alkyne group with H2O and some how produce the alcohol group.

Am I heading in the right direction?
 

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It's been a while since I've done Ochem, but here's my suggestion. Hydrate the alkyne, substitute a hydroxyl group with a halide using an equimolar amount of a selective halide salt, like PBr3. The resulting aklene will be on the 1,2 position, and a antimarkovnikov addition of an alcohol should add an alcohol onto the 1 position, creating your desired substance.

By the way, you drew the alkyne incorrectly. It's always drawn in a straight line due to sp hybridization.

EDIT: Actually, what I said was wrong. I was thinking about it on the way to class, removal of the halide will result in the 2,3 alkene, the hydrogen on carbon 2 (the one with the hydroxyl group) will be removed. I'll think about this more.
 
Last edited:
Hi!

STEP 1: convert the alkyne to an alkene using Na/liq.NH3 .
STEP 2: Use NBS(N-Bromosuccinimide) to get allyl bromide(CH3CH=CHCH2Br) which when reacted with aq.NaOH gives alcohol(CH3CH=CHCH2OH).
STEP 3: Acidic hydrolysis of this alcohol gives the required product.

Vineeth.
 
You're looking to form 1, 3 - butanediol I believe. I'm pretty sure you can mix an alkene with water to get an alcohol.

My organic chem is a bit rusty, but I believe (1 - hydroxy - 2 - butene) + H - OH should give you what you're looking for.
 

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