Organizing Physics Formulas for Assignment: Maximizing Marks

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The discussion centers on optimizing the presentation of physics formulas for an assignment, particularly in mechanics. Key formulas mentioned include f = m*a, a = (v-u)/t, and others related to motion and acceleration, such as x(t) = x_0 + v_0t + 1/2at^2 and v(t) = v_0 + at. The conversation emphasizes the importance of understanding these formulas in the context of drag racing, where acceleration is a critical factor. It highlights that while ideal conditions assume constant acceleration, real-world scenarios involve complexities such as traction limits and power limitations, affecting how vehicles perform over a quarter-mile. The discussion also touches on the implications of reaching maximum speed during a race and the potential need for gear changes to optimize performance. Overall, the focus is on applying these formulas effectively to achieve high marks in the assignment.
hazakate
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i have a few formula for my physics assignment but i want to know the best way to set it out and what other formula i can use.

i already have the formula f=m*a and a=(v-u)/t.
i just really need the marks
 
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Perhaps if you described what the assignment requires we would be of more help? You probably need a good grasp of mechanics, and that includes the formulas you list as well as some more. Here are just a few:

x(t) = x_0 + v_0t + \frac{1}{2}at^2
v(t) = v_0 + at
v = \frac{dx}{dt}
a = \frac{dv}{dt}
\Sigma F = ma

This might also be helpful:
http://hyperphysics.phy-astr.gsu.edu/hbase/mot.html#motcon
 
s = ut + 1/2 a t^2

For drag racing, u is zero. s is 1/4 mile (usually) (402.336 metres) so you get

402.336 = a/2 * t^2

t = sqrt(804.672 / a)

So you see that 1g (g = 9.81) acceleration will give you a 9 second run
or 5g would give a 4 second run

Real dragsters don't accelerate at a constant rate, but these formulae are ok as approximations.
 
You assume that the car accelerates not only constantly, but also throughout the race. Who's to say the car doesn't top at some value of V and proceeds with no acceleration at all?
 
Usually, car is first traction-limited, in which case, applied force F is constant:
mdv/dt=F-Cv^2
At some point, it becomes power -limited with P constant:
mdv/dt=P/v-Cv^2
C is aerodynamic drag coefficient. Aero drag is much more important than rolling resistance, so I ignore a C_2v term.
BTW, you will notice that C can be derived from top speed v_\infty (where dv/dt=0):
C=P/v_\infty^3
 
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thank you this helps
 
Chen said:
You assume that the car accelerates not only constantly, but also throughout the race. Who's to say the car doesn't top at some value of V and proceeds with no acceleration at all?

when that happens you
A shift a gear
or if in top gear

B change final drive gears

but very few cars will do that in top gear
ie reach top speed in less than a 1/4 mile
 
ray b has it. If the car reaches maximum speed before it hits the traps, the mechanics will work the car over by changing the gears in the rear-end.
 
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