Oscillatory Motion: Frequency 3.00, Amplitude 5.00 cm

AI Thread Summary
A particle in simple harmonic motion has a frequency of 3.00 oscillations/s and an amplitude of 5.00 cm. To determine the total distance moved in one cycle, the particle travels twice the amplitude, totaling 10.00 cm. The maximum speed can be calculated using the formula v_max = ωA, where ω is the angular frequency, leading to a specific value based on the given frequency. Maximum acceleration occurs at the endpoints of the motion and can be calculated using a = ω²A. To solve the problem effectively, it's essential to show relevant equations and work.
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Homework Statement



A particle moves in simple harmonic motion with a frequency of 3.00 oscillations/s and an
amplitude of 5.00 cm. (a) Through what total distance does the particle move during one cycle
of its motion? (b) What is its maximum speed? Where does this occur? (c) Find the maximum
acceleration of the particle. Where in the motion does the maximum acceleration occur?


Homework Equations





The Attempt at a Solution

 
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welcome to the physics forum!

I notice you've posted a problem but without any relevant equations or work you did.

We can't help you if you don't show some work.

First, draw a picture of what the problem is describing.

Is it a mass on a spring, or a pendulum...?
 

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