Osmotic Pressure & Mass Percent

AI Thread Summary
The discussion revolves around calculating the mass percentages of KCl, KNO3, and Ba(NO3)2 in a mixture based on its osmotic pressure and chlorine content. The osmotic pressure of 744.7 mm Hg was converted to 0.9799 atm, leading to the calculation of 0.0057 mol of ions per liter, assuming complete dissociation of the compounds. The user faced challenges in progressing from this point but eventually determined the number of moles of ions in the solution. They ended up creating two equations with different variables to solve for the mass percentages. The discussion highlights the complexities of using osmotic pressure to derive component concentrations in a mixture.
kuahji
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[SOLVED] Osmotic Pressure & Mass Percent

A solid mixture of KCL, KNO3, and Ba(NO3)2 is 20.92 mass percent chlorine, and a 1.000g sample of the mixture in 500.0 mL of aqueous solution at 25 C has an osmotic pressure of 744.7 mm Hg. What are the mass percents of KCl, KNO3, and Ba(NO3)2 in the mixture?

First I started out using osmotic pressure equation after I converted 744.7 mm Hg to atm.

.9799atm=7x(.08206 L*atm*K^{-1}*mol^{-1})(298K)

x=.0057 mol of ions/liter (I chose 7x because it appears there would be 7 ions, assuming they'd all dissociate completely)

Here however is where I'm stuck already. Any advice on where to go from here?
 
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kuahji said:
A solid mixture of KCL, KNO3, and Ba(NO3)2 is 20.92 mass percent chlorine, and a 1.000g sample of the mixture in 500.0 mL of aqueous solution at 25 C has an osmotic pressure of 744.7 mm Hg. What are the mass percents of KCl, KNO3, and Ba(NO3)2 in the mixture?

First I started out using osmotic pressure equation after I converted 744.7 mm Hg to atm.

.9799atm=7x(.08206 L*atm*K^{-1}*mol^{-1})(298K)

x=.0057 mol of ions/liter (I chose 7x because it appears there would be 7 ions, assuming they'd all dissociate completely)

Here however is where I'm stuck already. Any advice on where to go from here?

From here determine how many moles of ions are in half a liter.
 
I was able to figure it out from here, though it wasn't pretty. I ended up having to make two equations with two different variables. Thanks.
 
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