Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Parabolic Curve

  1. Dec 19, 2008 #1

    Just wondering if anyone could tell me how I would go about plotting the parabolic curve for the equation:


    Any help most appreciated

  2. jcsd
  3. Dec 19, 2008 #2


    User Avatar
    Science Advisor

    First of all, that's not an equation. Second, your notation is ambiguous.
    Do you mean
    [tex]f(c)= sigmaY*(1- \frac{(L/k)^2}{2}(L/k) c^2)= sigmaY*(1- (L/k)^3c^2/2)[/tex]
    [tex]f(c)= sigmaY(1- \frac{(L/k)^2}{2(L/k)} c^2= sigmaY*(1- (L/k)c^2/2)[/tex]
    [tex]f(x)= sigmaY(1- \frac{L/k)^2}{2(L/k)c^2}= sigmaY*(1- L/(2kc^2))[/tex]
    Since the last is not a quadratic and its graph is not a parabola, you must mean one of the first two. In either case, that is f(c)= A- Bc2 (what A and B are depends on which of the two you meant) which has vertex at (0, A) and opens downward.
  4. Dec 19, 2008 #3
    I will try and write the equation properly next time but I dont know how to use latex.

    Ok the equation I have is the third one? but with sigma instead of f(x).

    It is from a lab report and have been asked to draw the parabola for it. The original thread is here,


    Thanks for your help.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook