Parabolic trajectory of a rocket

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    Rocket Trajectory
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The trajectory of a rocket launched straight up is parabolic due to the influence of gravity acting on it after engine cutoff. While initially ascending vertically, rockets are steered and can achieve a ballistic trajectory that resembles a parabola once thrust ceases. The landing position of the rocket is influenced by its speed and thrust vectoring, which can cause it to land far from the launch pad. The discussion highlights that the trajectory can be viewed as part of an elliptical path, with Earth's center as one focus. Understanding these dynamics clarifies why rockets do not simply drop straight down.
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Why is the trajectory of a rocket always parabolic if a rocket launches straight up in the air perpendicular to the ground? Doesn't a rocket just drop straight down back to the launch pad? I think the rocket lands away from the launch pad depending on the speed of the rocket.
 
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I would consider that to be a special case of a parabola or a limit condition. And it does drop straight down (ignoring the Earth's rotation).
 
Russ,

What do you mean by limiting condition? So a rocket like an ICBM lands far away because of thrust vectoring?
 
A limit condition is a simplified special case - like a circle is to an ellipse.

And now I see your confusion - real rockets on launch pads tend to start off straight up. Yes, these rockets are steered. They don't end up on a ballistic (parabolic) trajectory until after their engines are stopped.
 
If v of the rocket is high. But v < \sqrt{\frac{2GM}{R}}
where M is the mass of Earth
R is the radius of Earth
The trajectory of the rocket is a part of ellipse because g is change accordingly to h (likes the trajectory of planet). One focus of this ellipse is the center of earth.
 
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