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## Homework Statement

## Homework Equations

I=Bmr^2

Parallel axis theorem = Icm + MD^2

WET, KE, PE equations

## The Attempt at a Solution

So far I've only done parts a and b and I wanted to post this up as soon as possible, I want to make sure if I'm on the right path so far.

part A) I know for this question I need to use the parallel axis theorem. What I did is I first found the moment of inertia of the rod first using I=(1/12)ML^2 , and also found the moment of inertia of the head (I=1/4MR^2 + 1/12ML^2). Then to find the moment of inertia of the mallet when held by the player at a distance of LP from the center of mass of the hammer, I derived the expression I

_{p}= (I

_{rod}+ I

_{head}+ (m

_{g}+ m

_{h})(L

_{p}+ 1/2L

_{g})

part B) For this part I'm thinking the work done by gravity is just the change in potential? where the total length (Lp + Lh + 1/2Rh - 1/2 if we were to just calculate up until the center of the mallet head) is used in a cosine equation to find h.

so

x = some change in height

(total length / total length + x) = cos65°

and I just solve for x and use that in the potential energy equation?