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combined resistance = sum of resistance * # of resistors

^{-2}

I checked wikipedia and there was nothing there above 2 resistors.

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In summary, the equation that's been posted does work for calculating the combined resistance of more than 2 resistors in parallel. However, if all of the resistors are the same, the equation reduces down to the simpler equation of R=n.

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combined resistance = sum of resistance * # of resistors

I checked wikipedia and there was nothing there above 2 resistors.

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In particular, look at the equation that begins

1/R_{total} = ...

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A way to derive the equation that's been posted is to realize that the voltage across each resistor is the same. Since we know the basic V=IR, we can figure out the current going to each resistor. The sum of the currents is going to be the same as the current of an equivalent resistance for the given voltage. So you get...

[tex]\frac{V}{R_1}+\frac{V}{R_2}+...+\frac{V}{R_n}=\frac{V}{R_{equivalent}} [/tex]. From there, just divide out the voltage V.

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hl_world said:

Only if all of the resistors are the same. Even then, your equation reduces down to...

[tex]R_{equivalent}=\frac{R}{n}[/tex] where n is the number of resistors.

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1

How can a path with

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Oh right; I see now. Thanks

The formula for calculating total resistance in a parallel circuit is **R _{t} = 1/(1/R_{1} + 1/R_{2} + 1/R_{3} + ... + 1/R_{n})**, where R

To calculate the equivalent resistance of two resistors R_{1} and R_{2} in parallel, use the formula **R _{eq} = (R_{1} x R_{2})/(R_{1} + R_{2})**.

The benefit of using parallel resistors in a circuit is that it allows for multiple paths for current to flow, resulting in a decrease in the total resistance and an increase in the overall current of the circuit.

No, the total resistance in a parallel circuit can never be lower than the smallest individual resistance. However, it can approach the smallest resistance as more resistors are added in parallel.

To calculate the total current in a parallel circuit, use the formula **I _{t} = I_{1} + I_{2} + I_{3} + ... + I_{n}**, where I

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