Parallel Resistors Problem: Total Current and Power Dissipation Calculation

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The problem involves two resistors, 16.0 Ohms and 20.0 Ohms, connected in parallel to a 12 V source. The equivalent resistance (Req) is calculated as 8.88 Ohms, leading to a total current of 1.35 Amperes from the source. Power dissipation in the 16.0 Ohm resistor is 9 Watts, while the 20.0 Ohm resistor dissipates 7.2 Watts. The calculations for current and power dissipation appear to be accurate. The discussion confirms the correctness of the solution.
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Homework Statement


Two resistors, 16.0 Ohms and 20.0 Ohms are placed in parallel with a 12 V source.

Homework Equations


What is the total current from the source and what is the power dissipated in each resistor?

The Attempt at a Solution


Req=(16*20)/(16+20) = 8.88 Ohms
V=Req*I
I=V/Req
I=12/8.88
I=1.35 Ampere

P1=V2/R1 = 122/16 = 9 W
P2=V2/R2 = 122/20 = 7.2 W
 
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chawki said:
Req=(16*20)/(16+20) = 8.88 Ohms
V=Req*I
I=V/Req
I=12/8.88
I=1.35 Ampere

P1=V2/R1 = 122/16 = 9 W
P2=V2/R2 = 122/20 = 7.2 W
'Looks correct to me. :approve:
 

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