Partial derivatives using definition

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SUMMARY

The discussion focuses on calculating partial derivatives using the definition, specifically for the function values at the point (2,3). The user successfully computed the first partial derivatives, f'x = 0 and f'y = 2, but encountered difficulties in finding the second partial derivatives f''xx, f''yy, and f''xy. The definition used for the first partial derivative is f'x(2,3) = lim (h-->0) [f(2+h,3) - f(2,3)] / h. The user seeks clarification on applying the same definition to compute the second partial derivatives.

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Homework Statement


We are given a table where showing the points x and y and values of a function f(x,y).
The function itself is not given.
I have to find the partial derivatives f'x, f'y, f''xx, f''yy and f''xy around the point (2,3).


Homework Equations


I have to use the definition :
f'x(2,3) = lim (h-->0) [f(2+h,3) - f(2,3)] / h


The Attempt at a Solution


Ok. So I easily found f'x and f'y. (h is found by looking at the xs and ys, h for f'x = -1 and 2 for f'y).
My problem is finding the f''. My teacher is the kind that shows one definition and gives one example. I don't know how to find the f''s.

If someone could just point the way, I'd be grateful.
Thanks!
 
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The definition of the second partials is just the partial derivatives of the first partials. Why couldn't you just use the same method as before?
 
Well I know. It's easy to find the partial derivatives when we have the function. That I can find.
But as I said, we have just done one example with the "definition", so I quite don't see how.

It's like d[df/dx]/dx
When you derivate the function you just assume y as constant.
But when it comes to lim f(a+h,b)-f(a,b)/h, I just don't know how to express it.

f'x = 0 and f'y = 2
f''xx(2,3) = f'x [f(2+h, 3) - f(2,3) /h]
= f(2+2h, 3) - f(2,3)/h ?

I don't know really.
And then again, I'm quite stupid :D
 

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