Partial fraction decomposition

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SUMMARY

The discussion focuses on the partial fraction decomposition of the expression \(\frac{2e^3}{(s^2 - 6s + 9)s^3}\). Participants clarify that the denominator can be factored into \(s\), \(s\), \(s\), \((s-3)\), and \((s-3)\), leading to five residuals. However, it is established that the correct factorization should include \(s\), \(s^2\), \(s^3\), \((s-3)\), and \((s-3)^2\). This correction is crucial for obtaining accurate residual values.

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Ry122
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Homework Statement



[tex]\frac{2e^3}{((s^2)-6s+9)*s^3}[/tex]

you can factorize the denominator into s,s,s,(s-3),(s-3)

that gives you 5 residuals.

the first 3 should all be the same value but that's apparently not correct, so where

am I going wrong?
 
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Hi Ry122! :smile:
Ry122 said:
you can factorize the denominator into s,s,s,(s-3),(s-3)

Your denominators need to be s s2 s3 s-3 and (s-3)2 :wink:
 

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