ElfenKiller
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Homework Statement
H(z) = \frac{6-z^{-1}}{1+0.5z^{-1}} + \frac{2}{1-0.4z^{-1}} = k + \frac{A}{1+0.5z^{-1}} + \frac{2}{1-0.4z^{-1}}
where A = (6-z^{-1}) is evaluated at z^{-1}=-2.
Homework Equations
Partial fraction expansion.
The Attempt at a Solution
Why is z^{-1} set equal to -2? I thought normally you use the terms in the denominators for z^{-1} ...