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Partial integral?

  1. Oct 20, 2005 #1
    Partial integral???

    Can someone help me figure out what this means? It's been forever since I've had any math classes.

    V= ay/(b2 + y2)

    Find the derivative in terms of a,b, and y

    Thanks so much!!
     
  2. jcsd
  3. Oct 20, 2005 #2
    Do you know what a derivative is? Nobody here is going to just do the problem for you, but if you show what you're having trouble with we'll try to help :smile:
     
  4. Oct 20, 2005 #3
    yes... For example if you had 2x^3 the derivative would be 6x^2.... When i do the derivative for the above equation I get:
    a(b^2-y^2)/(b^2+y^2)^2
     
  5. Oct 21, 2005 #4

    HallsofIvy

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    Use the "quotient rule": the derivative of [itex]\frac{f(y)}{g(y)} [/itex] is
    [tex] \frac{\frac{df}{dy}g(y)- f(y)\frac{dg}{dy}}{g^2}[/tex]
     
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