Partial sum of geometric series

realitybugll
Messages
39
Reaction score
0
ok so i know how to calculate the partial sum of a geometric series.

But let's say i only want to calculate the sum of every other term, how would i do this?

example:

.5^0+.5^1+.5^2+...+.5^n = (.5^(n+1) - 1)/(.5-1)

but what equation can i use to get the sum of only these terms:

.5^1+.5^3+.5^5...+.5^n where n is odd
 
Mathematics news on Phys.org
Hint:

See if you can re-write it as another geometric series, utilizing that an odd number n=2m+1, for m integer.
 
yea i actually need to do it for the even ones for my equation haha

ok so i think i got it, not going to write it all out because i;m busy, but thank you :)
 
And, of course, (.5)n, for n, even, n= 2m, is (.25)m so you have just another geometric series.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...

Similar threads

Replies
7
Views
2K
Replies
0
Views
2K
Replies
3
Views
1K
Replies
5
Views
2K
Replies
10
Views
2K
Replies
7
Views
3K
Back
Top