Particle in a uniform magnetic field

AI Thread Summary
To find the expressions for speed (v) and mass (m) of a charged particle moving in a uniform magnetic field, the relevant equations include kinetic energy (K = 1/2 mv^2) and the magnetic force (F = qvB = mv^2/R). The attempt at a solution suggests that 2K = mv^2 leads to the expression qvB = (2K)/R, which simplifies to v = (2K)/(qBR). However, there is confusion regarding the correctness of this expression for velocity, particularly in the context of special relativity. Clarification is needed on the assumptions made in the calculations and the applicability of the equations used. Understanding these relationships is crucial for accurately describing the particle's motion in the magnetic field.
bowdish.9
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Homework Statement


A particle with charge q and kinetic energy K travels in a uniform magnetic field of magnitude B. If the particle moves in a circular path of radius R, find expressions for speed, v, and mass, m.. (Use any variable or symbol stated above as necessary.)

Homework Equations


K=1/2mv^2 F=qvB=(mv^2)/R

The Attempt at a Solution


2K=mv^2 ---> qvB=(2K)/R ---> (2K)/(qBR)

Why is this incorrect?
 
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If this is supposed to be the velocity, it looks correct (if we do not include special relativity).
Why do you think it is incorrect?
 
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