What is the maximum speed an object can have without breaking a hanging string?

AI Thread Summary
The discussion revolves around calculating the maximum speed of a 3.00 kg object rotating in a circle while attached to a string that can support a 25.0 kg load before breaking. The participant initially struggles with the equations of motion, particularly in relating tension and centripetal force. After some confusion regarding the tension force, they correctly identify that the tension is equivalent to the force exerted by the 25.0 kg weight, leading to a calculation of 245 N for the tension. Ultimately, they derive the correct maximum speed, realizing their earlier misinterpretation of the tension value. The conversation concludes with the participant feeling confident about completing their homework.
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Homework Statement


A light string can support a stationary hanging load of 25.0kg before breaking. A 3.00kg
object attached to the string rotates on a horizontal table in a circle of radius .800m, and
the other end of the string is held fixed. What range of speed can the object have before
the string breaks?


Homework Equations


I have drawn a diagram and put these forces together.


The Attempt at a Solution


Sum of Forces in X=n and -mg
Sum of forces in Y= T and C sin theata

I know that the X canels out Fx = N-mg = 0
I get Y forces to be T + C sin theata = v^2/r

Am I starting this correct. Something doesn't seem right here.
Thanks,
Kevin
 
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The only force acting in the direction of the string would be the centripetal force, which is dependent on the velocity. Find the velocity which would cause the string to break. The maximum force for the string can be found with the known property that hanging 25kg will break it.
 
I do know that the forces in the x direction are Centripital Acceleration and tension
but I'm not sure how to put the equation together. F=ma
So does the Tension = m(v^2/r

Thanks,
Kevin
 
I get the force to be T=m(v^2/r)
So v = sqrt Tr/M
I get 2.58 m/s but the book says 8.08 m/s?

Not sure what I'm doing wrong
Thanks,
Kevin
 
I got it duh! I keep thinking that 25.0kg was the tension. But Tension is F=ma
F = (25.0kg)(9/8m/s2) = 245 N
That is the tension force.

Kevin
 
In this case...you know what to do from here on?
 
Thanks for looking Gear 300. I got it. Just one more to go to finish my homework.
It could be a rough one.

Kevin
 
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