Particle physics: energy conservation

kylie14
Messages
20
Reaction score
0
Hi,
I've managed to get extremely confused; I feel like I'm getting told different things! I hope someone can just clarify this for me.

If you have a reaction, say for example:
p pion+ --> p p
(where p is a proton) is it true that the rest mass afterwards must be less than the rest mass before or energy conservation is violated?
 
Physics news on Phys.org
No. The rest mass afterwards only need to be less than the total energy of the initial particles. You can accelerate very light particles, eg., electrons, to get large kinetic energy and produce heavy particles in the end.
 
You're thinking about 1 particle decaying into a product of particles. In that case, the rest mass of the decay products need to add to be less than the rest mass of the initial particle.

However, as already mentioned, when you have two particles colliding, they can have extra energy beyond their rest mass in the form of a relative momenta.

Also, the particular example you cited violates baryon number conservation.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top