Particles under constant acceleration

AI Thread Summary
A car decelerates uniformly at -5.60 m/s² for 4.20 seconds, covering a distance of 62.4 meters before hitting a tree. The initial calculations incorrectly set the final velocity to zero, leading to confusion in determining the speed at impact. By calculating the average velocity as 14.9 m/s, the correct approach involves using the kinematic equation to find the initial velocity. This results in an initial velocity of 26.6 m/s, and applying the average velocity formula yields a final speed of 3.10 m/s at the moment of impact. The discussion emphasizes the importance of correctly interpreting the problem to find the accurate speed.
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Homework Statement



Okay, wordy. Read through though, please :smile:

The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with an acceleration of -5.60 m/s^2 for 4.20s, making straight skid marks 62.4m long ending at the tree. At what speed does it hit the tree?

Homework Equations



Vf=Vi+at

The Attempt at a Solution



So I saw I had a=-5.60m/s^2, t=4.20s, xf=62.4m, and Vf=0 (since after he hit the tree, he stopped).

So I plugged them into Vf=Vi+at (or rather Vi=Vf-at), or 0-(-5.60)*4.20, to give 23.52 m/s. It seems wrong, though. Suggestions or advice?
 
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you jumped ahead by setting Vf to 0, you simply want to solve for Vf to find out what speed it is going when it hits the tree (as the question asks).

they also give you a time and distance, so you have an average velocity to help figure out the initial velocity in terms of the final velocity (or vice versa)After it hits the tree, it experiences another negative acceleration as it crumples against the tree, each piece of the car at different rates; but that would be a different problem all together.
 
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Oh...so I'm to find the average velocity, right? Umm...that's x/t, which is 62.4/4.20, which gives 14.9.

Then, I would have to find the initial velocity, uh huh? xf=xi+Vxit+1/2at^2...Vi=26.6.

Then Vavg=Vi+Vf/2 would come to play...14.9=26.6+x/2, gives a different answer, Vf=3.10m/s. It looks a little bit more correct, so thanks.
 
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