Partition Function: Energy States & Force Constants

AI Thread Summary
The discussion centers on calculating the partition function for a system with two harmonic potential wells characterized by different force constants, kA and kB. The proposed partition function is Z=e^(-hwA/2kT)+e^(-hwB/2kT), where wA and wB are derived from the respective force constants. A key question raised is how small kB must be relative to kA for the higher energy state to be more likely populated at a given temperature T. The conversation suggests that further exploration of the relationship between the force constants and temperature is necessary for a complete understanding. Overall, the thread seeks clarity on the implications of force constants on energy state populations within the context of statistical mechanics.
DanPhysChem
Messages
5
Reaction score
0
Hi All - If I have a potential energy surface with two energy states, one higher than the other, where I can make the assumption that both potential wells can be approximated via harmonic potentials with force constants kA and kB then would the partition function for the system be Z=e^(-hwA/2kT)+e^(-hwB/2kT) where wA=sqrt(kA/m) and wB=sqrt(kB/m)? Also, if the higher energy state was the more likely to be populated at some temperature T, how small would kB (the higher energy state) need to be in terms of kA?
 
Physics news on Phys.org
Anyone? Maybe I should have posted this in Advanced Physics.
 
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...
Back
Top