Passive Transport Homework: Solving Diffusion Problems

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Homework Statement



6enomg.jpg


2. The attempt at a solution

a) The particle seems to be 50 nm in diameter, so

<br /> D = \frac{k_BT}{6 \pi \eta R} = 4.4E-12 m^2s^{-1}<br />

b)

<br /> j_{diff}=-D\frac{dc}{dx} = -4.4E-12 \cdot \frac{dc}{dx}<br />

I don't know what to do next...Can I assume c(x) = c_0x? In that case,

<br /> j_{diff} = -4.4E-12 c_0<br />

Is this correct? What are the units?

And how to do c)?
 
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superwolf said:
I don't know what to do next...Can I assume c(x) = c_0x?

What does the continuity equation tell you about the flux in the tube? Hint: Fick's Second Law
 
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