PDE Help - Eigenfunction of a LaPlacian

In summary, we discussed eigenfunctions of the Laplacian on a specified region with homogenous boundary conditions. An example of an eigenfunction on the cube [0,π]^3 with Dirichlet BCs was given. We also explored a problem involving the heat equation and the use of d'Alamberts solution and ray-tracing. Finally, we discussed finding a function whose second derivative is equal to a negative constant times itself and whose values at 0 and π are 0. The function sin(x) was suggested as a solution for x = 0 and x = π, but further consideration is needed for the remaining variables.
  • #1
rexasaurus
14
0
1. A function "v" where v(x,y,z)≠0 is called an eigenfunction of the Laplacian Δ (on some region Ω - with specified homogenous BC) if v satisifies the BC ad also Δv=-λv on Ω for some number λ.

Part A: Give an example of an eigenfunction of Δ when Ω is the cube [0,∏]3 with Dirichlet BCs.
Part B: Show that, for any eigenfunction v, the function u(t,x,y,z)=cos(√λt)v(x,y,z) is the solution for the problem:
utt=ΔU on [0,T]XΩ with Ω=[0,∏]3
u=0 on ∂Ω for 0≤t≤T
{u(0,x,y,y)=v(x,y,z) for 0≤x,y,z≤∏}
{u(0,x,y,y)=0 for 0≤x,y,z≤∏}

2. We are studying heat equation, wave equation, eigenfunctions, d'Alamberts sol., ray-tracing, etc.

3. Okay... I am not sure how to approach a problem of this nature. I sketched the cube from [0,∏]. I am assuming that the answer is given in part B. I can see how the cosine function is always 0 at the BC's. Any help with this process would be appreciated.
 
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  • #2
Hint: Can you think of a function whose second derivative is minus a constant times itself and whose values at 0 and pi are zero?
 
  • #3
Sin(K*u)?? Second derivative would be -K2sin(K*u)

I am not sure which variable should be inserted for "u" since u is a function of x,y,z.
 
  • #4
LCKurtz said:
Hint: Can you think of a function whose second derivative is minus a constant times itself and whose values at 0 and pi are zero?

rexasaurus said:
Sin(K*u)?? Second derivative would be -K2sin(K*u)

I am not sure which variable should be inserted for "u" since u is a function of x,y,z.

Your independent variables are x,y, and z. In part A you are trying to match the boundary conditions. So u = sin(x) would take care of the x = 0 and x = π boundary conditions. What about the others?
 

Related to PDE Help - Eigenfunction of a LaPlacian

1. What is the LaPlacian operator and how does it relate to PDEs?

The LaPlacian operator, denoted as ∇², is a second-order differential operator commonly used in partial differential equations (PDEs). It is used to describe the curvature, divergence, and gradient of a scalar field in a multi-dimensional space. In PDEs, the LaPlacian operator is often used to describe diffusion processes and other physical phenomena.

2. What is an eigenfunction of a LaPlacian?

An eigenfunction of a LaPlacian is a function that, when acted upon by the LaPlacian operator, results in a scalar multiple of the original function. In other words, the eigenfunction is a special solution to the LaPlacian equation, where the solution is a multiple of the original function. These eigenfunctions are important in solving PDEs as they provide a basis for more complex solutions.

3. How are eigenfunctions of a LaPlacian found?

Eigenfunctions of a LaPlacian are found by solving the LaPlacian equation with appropriate boundary conditions. This typically involves solving a second-order linear differential equation and finding the appropriate values for the eigenvalue. In some cases, eigenfunctions can also be found using numerical methods.

4. What is the significance of eigenfunctions in PDEs?

Eigenfunctions play a crucial role in solving PDEs as they provide a basis for more complicated solutions. By finding the eigenfunctions of a LaPlacian, we can express a given PDE as a linear combination of these eigenfunctions, making it easier to solve. Eigenfunctions also have important physical interpretations, such as representing standing waves in a vibrating string or the energy levels of a quantum mechanical system.

5. Can the eigenfunctions of a LaPlacian be used to solve any PDE?

No, the eigenfunctions of a LaPlacian can only be used to solve certain types of PDEs, specifically those that can be expressed as a linear combination of the eigenfunctions. In other cases, different techniques such as separation of variables or numerical methods may be required to solve the PDE. It is important to carefully consider the boundary conditions and nature of the PDE before determining if the eigenfunctions of a LaPlacian can be used for its solution.

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