Rounding for 10% Error: (106 +/- 11) k^2 Hz^2?

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The discussion revolves around how to properly quote a frequency squared value of 106.01 k^2 Hz^2 with a 10% error. The proposed notation of (106 +/- 11) k^2 Hz^2 raises concerns about whether it accurately reflects the percentage error. It is noted that while 11 k^2 Hz^2 exceeds the 10% threshold, in practical terms, rounding to 11 is acceptable due to the insignificance of the extra decimal. However, for academic purposes, adherence to specific grading criteria may dictate that the more precise (106.0 +/- 10.6) k^2 Hz^2 is preferred.
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Homework Statement



the frequency squared is 106.01 k^2 Hz^2. The percentage error is 10 %. How do you quote the quantity

Homework Equations



I said (106.0 +/- 10.6) k^2 Hz^2

My question is rounding to (106 +/- 11) k^2 Hz^2 wrong? 11 k^2 Hz^2 seems to be more than 10 per cent. Thanks

The Attempt at a Solution

 
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Well, it's not much of a difference between 10.6% and 11%. In the real world, you'd probably write 106 ± 11 because giving more than two significant figures in the error is pretty useless.

But if this is a problem for a class... I couldn't guarantee that 106 ± 11 would be accepted as correct. Sometimes the rules used for grading homework problems don't quite correspond to real life. (Often for good reason, but sometimes not)
 
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