PERE'S LAW AND THE FREQUENCY OF ELECTRON BEAM IMPACTS ON METAL

[promiseskept]

Homework Statement

A beam of electrons is hitting a block of metal with current A. What is the frequency they are hitting the block?

Homework Equations

i=q/t

The Attempt at a Solution

i=q/t => 1/t=i/q. So then 1/t=A/e, where e is the elementary charge.
This may in fact be right. Our prof gave it to us as a question to think about and I want to know what everyone else is thinking.

 

[Andrew Mason]

Homework Statement

A beam of electrons is hitting a block of metal with current A. What is the frequency they are hitting the block?

Homework Equations

i=q/t

The Attempt at a Solution

i=q/t => 1/t=i/q. So then 1/t=A/e, where e is the elementary charge.
This may in fact be right. Our prof gave it to us as a question to think about and I want to know what everyone else is thinking.

Let dn/dt = the number of electrons per unit time flowing (ie. the frequency at which electrons hit the block).

What is the current in terms of dn/dt?

AM

 

[promiseskept]

Let dn/dt = the number of electrons per unit time flowing (ie. the frequency at which electrons hit the block).

What is the current in terms of dn/dt?

AM

Wouldn't that just be like I said, the current divided by the charge, thus saying how many electrons per unit time. [A]/[C] * e=[C*s]/[C]=1/[C] * e = 1/ electrons.

 

[Andrew Mason]

Wouldn't that just be like I said, the current divided by the charge, thus saying how many electrons per unit time. [A]/[C] * e=[C*s]/[C]=1/[C] * e = 1/ electrons.

It was not clear what you meant by t or 1/t. The number of electrons per second is the Current (in coulombs/sec or Amperes) divided by the charge of one electron (in Coulombs). If that is what you meant by 1/t then you were correct.

AM