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Agent M27
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Homework Statement
A 6 kg object moving with a speed of 9.9 m/s collides with a 19 kg object moving with a velocity of 7.2 m/s in a direction 24* from the initial direction of motion of the 6 kg object. What is speed of the two objects after the collision if they remain stuck together?
Homework Equations
Px = m1v1icos[tex]\theta[/tex]+m2v2icos[tex]\theta[/tex] = m1v1fcos[tex]\theta[/tex] + m2v2fcos[tex]\theta[/tex]
Py = m1v1isin[tex]\theta[/tex]+m2v2isin[tex]\theta[/tex] = m1v1fsin[tex]\theta[/tex] + m2v2fsin[tex]\theta[/tex]
The Attempt at a Solution
Edit I realized my original way was faulty in its logic.
So what I did was I began by finding the initial and final momenta components in both the x and y directions for the two particles. Being that they stick together their final velocity ought to be the same.
[tex]\Sigma[/tex]Pxi = m1v1cos[tex]\theta[/tex] + m2v2cos[tex]\theta[/tex]
=184.37302
[tex]\Sigma[/tex]Pyi = m1v1sin[tex]\theta[/tex] + m2v2sin[tex]\theta[/tex]
=55.641573
As I mentioned their final velocity should be equal since they are stuck together. Equating my initial momenta to my final momenta in the x direction I get the following:
Vf = [tex]\frac{(m1v1cos\theta + m2v2cos\theta}{(m1+m2)cos\theta}[/tex]
=8.072856 m/s
When I checked it using the momenta of the y direction I come to a different value for the final velocity which doesn't make sense so I know I made a mistake somewhere... Thanks in advance.
Joe
Edit: I tried a new way, but
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