Periods of Jacobi Elliptic functions

  • Thread starter Thread starter binbagsss
  • Start date Start date
  • Tags Tags
    Functions Jacobi
binbagsss
Messages
1,291
Reaction score
12

Homework Statement



I have that ##(\psi(z)-e_j)^{1/2}=e^{\frac{-n_jz}{2}}\frac{\sigma(z+\frac{w_j}{2})}{\sigma(\frac{w_j}{2})\sigma(z)}##

has period ##w_i## if ##i=j##
and period ##2w_i## if ##i\neq j##

where ##i,j=1,2,3## and ##w_3=w_1+w_2## (*)
where ##e_j=\psi(\frac{w_j}{2})##

I have the following (two) identities:

##\sigma(z+w_j)=-\sigma(z)e^{n_j(z+\frac{w_j}{2})}## (1)

From which we can get:

##\sigma(z+\frac{w_j}{2})=-e^{n_j z}\sigma(z-\frac{w_j}{2})## (2)

With the above information I need to deduce that:

##S(z)## has period lattice with ##(2w_1,w_2)##
##C(z)## has period lattice with ##(2w_1,w_1+w_2)##
##D(z)## has period lattice with ##(w_1,2w_2)##

where ##S(z), C(z), D(z)## are given as attached:

attachhere.png


Homework Equations



see above, see below, look up, look down, look all around.

The Attempt at a Solution



[/B]

My book says this is straightforward with the result (*) stated above. But I can't see it for ##C(z) ## and ##D(z)##...

For example,

##C(z)## numerator, using (*), has periods ##(w_1,2w_2)##, whilst the denominator has periods ##(2w_1,w_2)##..

So I can't see how a obvious conclusion can be made? (Similarly for ##D(z)##)...
All I can see to do is work through a tonne of algebra, each period in turn, using (1) and (2), however then I'm not making use of (*), from which my book says the result simply follows, so I don't think I should be needing to do this anyway...

Many thanks in advance.
 
on Phys.org
bump.
 

Similar threads

Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K