Permutation question with a dial

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The discussion revolves around calculating the number of ways to connect numbers on a circular dial numbered 1 to 12. The initial solution proposed involves creating 6 pairs by connecting each number to one three numbers away, resulting in 66 possible connections through 6 pairs and 11 offsets. The poster seeks a more mathematical approach using factorials and references a video about permutations related to the Enigma code. They attempted to apply the logic from the video but did not achieve the expected result of 66 using the formula 12!/(6!^2 * 2^6). The conversation emphasizes the need for alternative methods to solve the pairing problem mathematically.
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Homework Statement



So, you have a dial with 12 numbers (1 through 12), and you're wondering how many ways can you connect an number to another. So its therefor asking how many lines can you make with 1 - 12 in a circle.

Homework Equations





The Attempt at a Solution



I got the solution, I made 6 pairs one number to the one 3 numbers away from it (in a circular manner) and I knew if I were to offset everything by one id next a combination, and I could do this 11 times.

6 pairs * 11 offsets = 66 possible lines.


But I was wondering how to do this in a more mathematical manner (with factorials.) And I watched this interresting video on the enigma code "http://www.youtube.com/watch?v=G2_Q9FoD-oQ".

So I tried the same logic on the permutation the man used for the 26 letters. I attempted
12!/(6!^2 * 2^6) and didn't get 66.

How would you solve this using the logic that video used on the Engima code. I would simply like to know other ways to solve this equation
 
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