Permutations: Arranging Red, Green & Gray Books on a Shelf

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AI Thread Summary
The discussion centers on arranging books of different colors on a shelf, specifically 4 red, 3 green, and 2 gray. The key point is that books of the same color must be grouped together, leading to a calculation of arrangements. One participant initially suggests the answer is 3!, which is only correct if color groups are treated as single units. The correct formula for this arrangement is 4!3!2!3!, indicating the need to account for both the internal arrangements of color groups and the arrangement of those groups themselves. Clarity in the question's wording could have avoided confusion regarding the arrangement rules.
Government$
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Homework Statement



1.) 4 of the books have red covers, 3 have green covers, and another 2 have gray covers. In how many ways can the books be arranged on a shelf if books of the same color must be arranged together?


The Attempt at a Solution



1) I think that the answer here is 3!

But here is the answer from my book (4!3!2!)3!
 
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Hi Government$! :smile:
Government$ said:
1.) 4 of the books have red covers, 3 have green covers, and another 2 have gray covers. In how many ways can the books be arranged on a shelf if books of the same color must be arranged together?

1) I think that the answer here is 3!

That's correct only if books of the same colour are stuck together! :wink:
 
If the answer they are looking for is 4!3!2!3! it would have been less ambiguous to pose the question as "There are 9 different books. 4 of the books have red covers...".
 
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