How to Prove the Uniqueness of Perpendicular Lines in Protractor Geometry?

AI Thread Summary
In protractor geometry, given a line l and a point B on l, there exists a unique line l' that is perpendicular to l at B. To prove this, one must demonstrate both the existence of at least one perpendicular line and the uniqueness of that line. The uniqueness can be shown by assuming the existence of two distinct perpendicular lines through B and demonstrating that this leads to a contradiction. The discussion emphasizes the importance of understanding the definitions of perpendicular lines and the geometric properties involved. Ultimately, the goal is to establish that only one line can be perpendicular to another at a given point.
Lee33
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Homework Statement


Given a line ##l## and a point ##B\in l## in a protractor geometry, there exists a unique line ##l'## that contains ##B## such that ##l\perp l'.##

Homework Equations



None

The Attempt at a Solution



I am not sure how to prove uniqueness or existence in this theorem.

We say lines ##l## and ##m## in a protractor geometry are perpendicular, denoted ##l\perp m##, if ##l\cup m## contains a right angle.
 
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The Attempt at a Solution



Understanding the problem:

B is a unique point on the line ##l##. A line is made up of many points. A unique perpendicular line ##l'## means a line that does not contain points that are in line ##l## except the point B. So we try to prove that a line ##l## is perpendicular to another line ##l'## then they should have only one point in common which is B. I can only prove with examples so

Take a line in the form y = mx + c then select a point B (any point) then draw the perpendicular line at the point B. By inspection you will see that the two lines only intersect at the point B. They will never intersect anywhere else so the two lines are unique except at the point B.
 
PcumP_Ravenclaw said:
B is a unique point on the line l
We need to show that the perpendicular is unique, not the point B.

The usual style for proving uniqueness is to assume that opposite of the conclusion; i.e., that the perpendiculars are not unique, and show that this assumption leads to a contradiction. The contradiction means that the assumption must have been incorrect, so you are left with a single perpendicular.

Given a line L and a point B on L, assume that distinct lines L1 and L2 go through B and are perpendicular to L. Can you show that this assumption leads to a contradiction? If so, you will have proved the statement by contradiction.
 
Lee33 said:

Homework Statement


Given a line ##l## and a point ##B\in l## in a protractor geometry, there exists a unique line ##l'## that contains ##B## such that ##l\perp l'.##

Homework Equations



None

The Attempt at a Solution



I am not sure how to prove uniqueness or existence in this theorem.

We say lines ##l## and ##m## in a protractor geometry are perpendicular, denoted ##l\perp m##, if ##l\cup m## contains a right angle.

There are two things to prove here:
(1) There exists at least one perpendicular of the type you describe; and
(2) There does not exist more than one such perpendicular.

If I were doing the question, I would begin by trying to show (1).
 
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