mnb96
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Hi,
given a complex vector space with a hermitian inner product, how is the cosine of the angle between two vectors defined?
I tried to follow a similar reasoning as in the real case and I got the following:
cos(\theta)=\mathcal{R}e \frac{ \left\langle u,v\right\rangle}{\left\|u\right\| \left\|v\right\|}
Does this make any sense?
If that is correct it means two vectors are perpendicular whenever the real part of their hermitian inner product is zero.
Again, if that is correct, how can we compute the projection of one vector onto another?
Thanks!
given a complex vector space with a hermitian inner product, how is the cosine of the angle between two vectors defined?
I tried to follow a similar reasoning as in the real case and I got the following:
cos(\theta)=\mathcal{R}e \frac{ \left\langle u,v\right\rangle}{\left\|u\right\| \left\|v\right\|}
Does this make any sense?
If that is correct it means two vectors are perpendicular whenever the real part of their hermitian inner product is zero.
Again, if that is correct, how can we compute the projection of one vector onto another?
Thanks!