Peskin Schroeder: How to Derive Sin^2 Using Compton Relation?

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Dear PF,

I have one question form Peskin Schroeder...could you pls help me
It is very simple question...
Since I don't know how to write formulas here I put my question in attachment.

Thank you very much.
 

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Well just use the fact that pk=m\omega and pk'=m\omega' plus the Compton relation

\frac{1}{\omega}-\frac{1}{\omega'}=\frac{\cos\theta - 1}{m}

And you'll get that -sin^2 after using a bit of trigonometry.
 
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