Understanding Phase Shift Upon Reflection: A Closer Look at Fresnel's Equations

AI Thread Summary
Light reflects at an interface with a phase shift depending on the refractive indices of the two media: a 180-degree phase shift occurs when light moves from a medium with a lower refractive index (n1) to a higher one (n2), while no phase shift occurs when n1 is greater than n2. For monochromatic light incident on a film, constructive interference occurs at thickness d = λ0/(4n) due to a net phase difference of zero, while destructive interference occurs at d = 2λ0/n, resulting in a 180-degree phase difference. The discussion also touches on the application of Fresnel's equations to demonstrate these phase shifts. The relationship between film thickness and interference patterns is crucial for understanding optical phenomena in thin films. Overall, the phase shift upon reflection is a key factor in determining interference effects in various optical systems.
dimensionless
Messages
460
Reaction score
1
Let's say I have light at normal incidence. Under what circumstances is there a phase shift? Under what circumstances is there no phase shift? My best guess is that there is normally a phase shift of 180 degrees. The exception is when n_incident > n_reflected, but I don't really know.

To elaborate more, let's say I have monochormatic light normaly incident on a film. Why do I get a maximum when the film thickness is d = \frac{\lambda_0}{4n} and a minimum when the film thickness is d = \frac{2\lambda_0}{n}.
 
Last edited:
Physics news on Phys.org
dimensionless said:
Let's say I have light at normal incidence. Under what circumstances is there a phase shift? Under what circumstances is there no phase shift? My best guess is that there is normally a phase shift of 180 degrees. The exception is when n_incident > n_reflected, but I don't really know.
Right. When light goes from one medium (n_1) to another (n_2), the reflected light at that interface undergoes a phase change as follows:
if n_1 < n_2: 180 degree phase change
if n_1 > n_2: no phase change​

To elaborate more, let's say I have monochormatic light normaly incident on a film. Why do I get a maximum when the film thickness is d = \frac{\lambda_0}{4n} and a minimum when the film thickness is d = \frac{2\lambda_0}{n}.
Looks like you are talking about a situation, like a soap film in air, where n_1 < n_2 > n_1. There are two reflections: the first has phase change; the second does not. So if the optical path length through the film is 1/2 \lambda (your first example), then the total phase difference between the reflections is zero and you get maximum constructive interference. Similarly, if the optical path length is an integral number of wavelengths (as in your second example), the net phase difference is 180 degrees: maximum destructive interference.
 
I have a question that is somewhat related. Regarding the phase shift upon reflection, how do you show that it is 180 degrees when n1 < n2 and 0 degrees when n1 > n2 using Fresnel's equations? Something along the lines of an informal proof.
 
Thread 'Help with Time-Independent Perturbation Theory "Good" States Proof'
(Disclaimer: this is not a HW question. I am self-studying, and this felt like the type of question I've seen in this forum. If there is somewhere better for me to share this doubt, please let me know and I'll transfer it right away.) I am currently reviewing Chapter 7 of Introduction to QM by Griffiths. I have been stuck for an hour or so trying to understand the last paragraph of this proof (pls check the attached file). It claims that we can express Ψ_{γ}(0) as a linear combination of...
Back
Top