Phase Spectra from Fourier Transform

AI Thread Summary
The discussion focuses on how to interpret phase spectra from a Fourier Transform, specifically for the function g(t) = Sin(2πf_ct). It highlights that the single-sided spectrum has a frequency component at f = f_c with a complex amplitude of 1/j, which corresponds to a phase of π/2. However, considering 1/j as -j leads to a phase of 3π/2, raising the question of which amplitude is correct. The correct method to determine the phase is to use the arctangent of the ratio of imaginary to real components, rather than relying solely on the complex plane representation. Ultimately, this approach reveals that the phase for the impulse at f = f_c is -π/2, while at f = -f_c it is +π/2.
frenzal_dude
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How can you read the phase spectra from a Fourier Transform?

if g(t) = Sin(2\pi f_{c}t)

then for the single sided spectrum, you have one frequency component at f=f_{c} with a height of \frac{1}{j} which from looking at the complex plane, corresponds to a phase of \frac{\pi }{2} (ie. g(t) = Sin(2\pi f_{c}t) is made up of a cosine component with f=f_{c} and phase = \frac{\pi }{2}.

But, if you consider \frac{1}{j} = -j, then the phase would correspond to \frac{3\pi }{2} which would in effect negate the amplitude (Cos(x - \frac{3\pi }{2}) = -Cos(x - \frac{\pi }{2}).

So which complex amplitude should be considered correct?\frac{1}{j} or -j ?
 
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frenzal_dude said:
How can you read the phase spectra from a Fourier Transform?

if g(t) = Sin(2\pi f_{c}t)

then for the single sided spectrum, you have one frequency component at f=f_{c} with a height of \frac{1}{j} which from looking at the complex plane, corresponds to a phase of \frac{\pi }{2} (ie. g(t) = Sin(2\pi f_{c}t) is made up of a cosine component with f=f_{c} and phase = \frac{\pi }{2}.

But, if you consider \frac{1}{j} = -j, then the phase would correspond to \frac{3\pi }{2} which would in effect negate the amplitude (Cos(x - \frac{3\pi }{2}) = -Cos(x - \frac{\pi }{2}).

So which complex amplitude should be considered correct?\frac{1}{j} or -j ?

I've worked it out (for anyone whose found this in a google search or something).

To find the phase spectra you need to take the arctangent of the ratio of imaginary to real components, and NOT merely look at the position of the vector on the complex plane.

So first you need to get those imaginary components to have j on the numerator instead of on the denominator, that way you know the coefficient of it.

So for Sin(sPIfct) the impulse at f=fc has an imaginary coefficient of -1/2, so the ratio of imaginary to real is -infinity (since there is no real part, real=0), arctan of -infinity = -PI/2 radians.

For the impulse at f=-fc, the coefficient of the imaginary component is 1/2, the ratio is +infinity, arctan of +infinity = +pi/2 :)
 
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