Phasor to sinusoid conversion help

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In summary, to convert a phasor to a sinusoid, use the formula e^jωt = cos(ωt) + j*sin(ωt) and replace ω with the frequency of the phasor. The purpose of this conversion is to represent complex numbers in a simpler and more intuitive way. An example of this conversion is 5*cos(ωt+30°) + j*5*sin(ωt+30°) for a phasor with magnitude 5 and phase angle of 30 degrees. This conversion can be applied to AC circuits to analyze their behavior. However, it has limitations such as only being applicable to sinusoidal signals and not taking into account transient or non-steady
  • #1
bryanhpaul
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Convert the following phasor to sinusoid:

V = 169\angle-45degrees where f = 60Hz

The answer given is 169cos(377t - 45degrees) V

I am sure I am missing something, but how does the frequency go from 60 to 377?
 
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  • #2
You just multiply by 2(pi). :)
 
  • #3
A little bit more detail, to expand on dstorm's post:

$$\omega = 2\pi f,$$
where $\omega$ is the angular frequency (that shows up multiplying $t$ in the waveform), and $f$ is just the frequency. Typically, the units will be a tip-off: $f$ is usually measured in Hz, whereas $\omega$ is usually measured in rad/s.
 

Related to Phasor to sinusoid conversion help

1. How do I convert a phasor to a sinusoid?

To convert a phasor to a sinusoid, you will need to use the formula e^jωt = cos(ωt) + j*sin(ωt). Replace the value of ω with the frequency of the phasor and then solve for the real part (cosine) and imaginary part (sine). The resulting expression will be the sinusoid form of the phasor.

2. What is the purpose of converting a phasor to a sinusoid?

Converting a phasor to a sinusoid allows us to represent a complex number in a more simplified and intuitive way. Sinusoids are easier to manipulate and analyze, making it easier to understand the behavior and characteristics of the phasor.

3. Can you provide an example of phasor to sinusoid conversion?

Sure, let's say we have a phasor with a magnitude of 5 and a phase angle of 30 degrees. To convert it to a sinusoid, we use the formula e^jωt = cos(ωt) + j*sin(ωt) and plug in the values of ω (in this case, it would be the frequency of the phasor) and solve for the real and imaginary parts. The resulting sinusoid would be 5*cos(ωt+30°) + j*5*sin(ωt+30°).

4. Can phasor to sinusoid conversion be applied to AC circuits?

Yes, phasor to sinusoid conversion is commonly used in AC circuit analysis. Phasors can represent the magnitude and phase of a sinusoidal voltage or current in a circuit, making it easier to analyze and calculate the overall behavior of the circuit.

5. Are there any limitations to phasor to sinusoid conversion?

One limitation of phasor to sinusoid conversion is that it can only be applied to signals that are sinusoidal in nature. If the signal is not a pure sinusoid, then the resulting sinusoid may not accurately represent the original phasor. Additionally, phasor to sinusoid conversion does not take into account any transient or non-steady state behavior of the signal, which may be important in certain applications.

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