[PhD Qualifier] Commutation relation

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SUMMARY

The discussion centers on the commutation relation between two quantum mechanical operators, denoted as [\hat{A},\hat{B}]=i. The conclusions drawn include that the operators are not simultaneously diagonalizable (a is false), they satisfy the Heisenberg uncertainty relation (b is true), they may or may not be spin operators (c is uncertain), and the Hamiltonian \hat{H}=\hat{A}^2+\hat{B}^2 can describe a harmonic oscillator system (d is true). The derivation of the uncertainty relation involves invoking the Schwartz inequality.

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  • Understanding of quantum mechanics principles, particularly operator theory.
  • Familiarity with commutation relations and their implications.
  • Knowledge of the Heisenberg uncertainty principle.
  • Basic concepts of Hamiltonian mechanics in quantum systems.
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  • Study Griffith's "Quantum Mechanics" for a detailed derivation of the uncertainty principle for arbitrary operators.
  • Explore the implications of non-commuting operators in quantum mechanics.
  • Research the properties of spin operators and their commutation relations.
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Quantum mechanics students, physicists, and anyone studying operator theory and the implications of commutation relations in quantum systems.

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Homework Statement



Two quantum mechanical operators obey the following commutation relation.
[\hat{A},\hat{B}]=i​
Given this commutation relation which of the following are true or false? Justify your answers.
a) The two observables are simultaneously diagonalizable.
b) The two satisfy a Heisenberg uncertainty relation that has the form
\left<(\Delta\hat{A})^2\right>\left<(\Delta\hat{B})^2\right>\ge\frac{1}{4}
c) They are spin operators.
d) The Hamiltonian \hat{H}=\hat{A}^2+\hat{B}^2 could describe a harmonic oscillator system.

Homework Equations



The Attempt at a Solution


a) False - simultaneously diagonalizable ==> simultaneously observable. Since they don't commute, they aren't simultaneously observable and can't be simultaneously diagonalizable.
b) No idea how to get there from here
c) They could be, but don't have to be. They satisfy a commutation relation for angular momentum (as do spin operators), but other angular momentum operators also satisfy the relation.
d) True. Dropping a factor of \hbar, A and B could be position and momentum operators (respectively), which gives a Hamiltonian of H=X^2+P^2.

I could use a hint or two on b, as well as someone verifying my logic for a, c, and d. Thanks!
 
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For b., and any other Heisenberg type relation, you need to invoke the schwartz inequality.
 
I suppose I can answer (b) using my observation from (d).

Let A=\frac{X}{\hbar}, B=P. Heisenberg's relation is \Delta x\Delta p \ge \frac{\hbar}{2}, so \Delta a\Delta b\ge\frac{1}{2}. Square it to get "true".

Can someone verify these answers for me?
 
I will tell you that b is true, but that's a tremendously ad hoc way to determine it.

If you have Griffith's "Quantum Mechanics" he performs the full derivation the uncertainty principle for two arbitrary operators.
 

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