Phonon Dispersion Relation: Reflection of Photons Explained

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SUMMARY

The discussion centers on the phonon dispersion relation and its impact on photon reflection and absorption in solids. It is established that the optical branch of the dispersion relation is non-zero at k = 0, leading to the conclusion that solids can be transparent to most photon wavelengths, except for those corresponding to the energy of optical phonons at k = 0. Approximately 90% of incident photons are reflected due to the strong interaction between infrared photons and optical phonons, which behave like large electrical dipole oscillators.

PREREQUISITES
  • Understanding of phonon dispersion relations
  • Knowledge of Brillouin zones in solid-state physics
  • Familiarity with optical phonons and their properties
  • Basic principles of photon behavior in materials
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  • Research the role of optical phonons in photon absorption and reflection
  • Study the concept of Brillouin zones and their significance in solid-state physics
  • Explore the interaction between electromagnetic waves and dipole oscillators
  • Learn about the mathematical modeling of phonon dispersion relations
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This discussion is beneficial for graduate students in physics, materials scientists, and researchers focusing on photonics and solid-state interactions.

Goodver
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in the dispersion relation curve for phonon, optical branch is not zero at k = 0. Thus generally speaking solid might be transparent for all photon wavelengths except the wavelength which corresponds to the energy of an optical phonon at k = 0. Thus photons can be absorbed or reflected. It says that about 90 percents of photons are reflected. Why?

Also, It is not clear for me how photon can be reflected? It requires to change the direction of the k vector, to opposite direction. Or is it that incident photon converts to optical phonon, which then converts to optical photon in opposite direction statistically?

I am on a master level.
Thank you.
 
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The momentum of infrared photons is negligible. The optical phonons near the center of the Brillouin zone are like large electrical dipole oscillators, which gives a very strong interaction with the electromagnetic waves.
 
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