Photoelectric effect and Aluminum

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Homework Help Overview

The discussion revolves around a thermodynamics problem involving heat transfer between a sample of aluminum and water, with a specific focus on comparing the heat liberated by aluminum to the heat absorbed by water. The context includes specific heat capacities and initial temperatures of both substances.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between heat transfer in aluminum and water, questioning whether the heat absorbed by water is greater, smaller, or the same as that liberated by aluminum. There are inquiries about the definition and units of heat, as well as comparisons to other scenarios involving mass transfer.

Discussion Status

The discussion is ongoing, with participants raising questions about the nature of heat and its measurement. Some have offered insights into the problem, while others express confusion about the relevance of the photoelectric effect to the thermodynamic scenario presented.

Contextual Notes

Participants note the assumption to neglect the heat absorbed by the container, which may influence their reasoning. There is also a suggestion that the problem may contain an underlying trick or connection to the photoelectric effect that remains unexplored.

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A 0.4 kilogram sample of Aluminum at 115 degrees Celsius is put into a container containing 0.5 kilograms of water at 15 degrees Celsius. Neglecting the small amount of energy absorbed by the container and knowing that the specific heat of Aluminum is 900 kJ/kg*C, and the specific heat of the water is 4186 kJ/kg*C answer the following question.

Compared to the heat liberated by the aluminum, the heat absorbed by the water is

greater. wrong

smaller.

the same.

is it smaller or the same?
why?
 
Last edited:
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what are the units of heat? what then is heat?
 
heat is...energy, thermal energy, or a change in temperature, measured in Joules
 
and what things have you learned about energy?
 
It is exactly the same with the following example. You pour a cup of water into a bucket. Then asked: compare the mass gained by the bucket and the mass lost by the cup. The answer now so simple.
 
It's the same since they already told you to ignore the heat absorbed by the container.
 
Hmmm... why is this a question about the photoelectric effect? It seems to be just a thermodynamics question, perhaps there's a trick somewhere?
 

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