Photoelectric Effect: Intensity & Frequency Effects

AI Thread Summary
The photoelectric effect requires that the minimum work function be met for electron emission, with intensity not influencing this threshold. Once the frequency exceeds the work function, increasing intensity should lead to a constant current, as the number of emitted electrons remains the same. Higher intensity results in more photons striking the metal, which correlates to a greater number of emitted electrons. The relationship between intensity and current is defined by the equation I = q/t, where more photons lead to increased electron emission. Understanding these dynamics is crucial for grasping the photoelectric effect's implications in physics.
Ukitake Jyuushirou
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hello

from my understanding of the photo electric effect, the minimum workfunction must be met before electrons are emitted prior to that, intensity doesn't play a part. if the frequency is increased to juz above the work function and stays constant there and i increase the intensity shouldn't the current detected be constant and the number of electrons emitted per second is the same?
 
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If the photons hitting the metal have enough energy to emit photons then the bigger the intensity the bigger the current. Cause more intensity means that more photons are hitting the metal. That means that more electrons are emitted: I = q/t
 
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