Photon Momentum Calculation for 25 x 105 erg Energy

  • Thread starter Thread starter melissajohn
  • Start date Start date
  • Tags Tags
    Momentum
AI Thread Summary
To calculate the momentum of a photon with energy of 25 x 10^5 erg, the formula p = E/c is used, where p is momentum, E is energy, and c is the speed of light. Photons are massless, so traditional momentum equations like p = mv do not apply. The energy unit erg is part of the cgs system, while the SI unit of energy is the joule. By substituting the values into the equation, the calculated momentum is approximately 8.3 x 10^-3 erg*m/s. This method effectively demonstrates how to derive photon momentum from energy.
melissajohn
Messages
20
Reaction score
0
how do you calculate the momentum if the energy of photon is 25 x 105 erg?

i know p=mass*velocity
but i am not sure how to do this problem.

is the SI units of photons... erg? i just want to make sure.
 
Physics news on Phys.org
melissajohn said:
how do you calculate the momentum if the energy of photon is 25 x 105 erg?

i know p=mass*velocity
but i am not sure how to do this problem.

is the SI units of photons... erg? i just want to make sure.

What are ergs? Units of energy? units of mass distance and distance/sec2

And rearranging what is that mass * distance2/s2?

And Einstein's famous equation is E= ... what? mass times what?

And what units is that?
 
The SI unit of energy is the joule. An erg is a unit of energy in the cgs system where you use centimetres, grams, and seconds (hence cgs) as the fundamental units of length, mass and time, INSTEAD of metres, kilograms, and seconds.

Photons don't have mass, but they do carry momentum. This may seem strange, but it's because a photon's momentum is NOT given by p = mv. This equation is NOT valid for massless particles such as photons. You need to find out the relationship between energy and momentum for a photon.
 
ergs - yes units of energy.
what do you mean rearranging the equation?
Einstein equation is e=mc^2?
 
melissajohn said:
ergs - yes units of energy.
what do you mean rearranging the equation?
Einstein equation is e=mc^2?

I was merely pointing out that energy was in the same units you would find in the E=mc2

But that's not all because from that you can also come up with an expression for the momentum. While a photon has no mass it can be expressed as E = p*c or p=E/c.

Knowing the units of ergs and the speed of light in the same units then you might be able to determine the answer.
 
ok so...
if i want to calculate the momentum if the energy of photon is 25 x 105 erg

I would get...

p=E/c
(25*10^5 erg)/(3*10^8 m/s)= 8.3*10^-3 erg*m/s

is that correct?

thanks!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top