- #1
StarThrower
- 220
- 1
Suppose the time dilation formula is true:
\Delta t = \frac{\Delta t^\prime}{\sqrt{1-v^2/c^2}}
if v = c then the denominator is zero.
If the denominator is zero and there is division by zero error then the numerator is nonzero.
If the denominator is zero and there isn't division by zero error then the numerator is zero.
Assume the time dilation formula doesn't lead to division by zero error.
Thus, if the denominator in the formula is zero then the numerator is zero.
Consider a photon moving through an inertial reference frame.
By the fundamental postulate of the theory of special relativity, the speed of this photon is c.
It follows that the denominator is zero. For the theory of special relativity to avoid self-contradiction, it follows that the numerator must be zero.
Thus, if there were a clock attached to a photon that moves along with a photon, that clock cannot be ticking (since delta t` is an amount of time measured by a clock moving at speed v in an inertial reference frame).
Thus, any clock moving along with a photon, cannot be ticking.
A photon has an intrinsic frequency. Thus, something within the photon is cycling at regular intervals. Thus, a photon constitutes a clock which is ticking.
This contradiction indicates that there is an error in the special theory of relativity.
Regards,
The Star
\Delta t = \frac{\Delta t^\prime}{\sqrt{1-v^2/c^2}}
if v = c then the denominator is zero.
If the denominator is zero and there is division by zero error then the numerator is nonzero.
If the denominator is zero and there isn't division by zero error then the numerator is zero.
Assume the time dilation formula doesn't lead to division by zero error.
Thus, if the denominator in the formula is zero then the numerator is zero.
Consider a photon moving through an inertial reference frame.
By the fundamental postulate of the theory of special relativity, the speed of this photon is c.
It follows that the denominator is zero. For the theory of special relativity to avoid self-contradiction, it follows that the numerator must be zero.
Thus, if there were a clock attached to a photon that moves along with a photon, that clock cannot be ticking (since delta t` is an amount of time measured by a clock moving at speed v in an inertial reference frame).
Thus, any clock moving along with a photon, cannot be ticking.
A photon has an intrinsic frequency. Thus, something within the photon is cycling at regular intervals. Thus, a photon constitutes a clock which is ticking.
This contradiction indicates that there is an error in the special theory of relativity.
Regards,
The Star
