I Photonuclear reaction & Conservation of momentum

oksuz_
Messages
70
Reaction score
3
γ+2D ----> 1H + 1n

In this photonuclear reaction, is it possible to write the momentum balance equation as it follows,

MHvH = Mnvn

It somehow seems to wrong to me, since the incoming photon has a certain momentum, which is not taken account in the balance equation.

Thank you in advance.
 
Last edited:
Physics news on Phys.org
Your original "equation" is not. The momentum balance is not too clear - what particles are you referring to? The outgoing particles (n and p) have momenta which sum to the momentum of te photon, assuming D is stationary.
 
I am sorry about the "+" mark between D and H. just edited it. Both incoming and outgoing particles are in motion. We should consider the momentum of the photon, should not we?
 
For typical photon energies, the photon momentum is tiny compared to the momenta of the proton and neutron.
 
If you ignore the photon momentum, the outgoing (n and p) have the same momentum,but in opposite directions.
 
Thank you all for answering. I should have thought this before. I have made a rough calculation. There is around eight orders of magnitude difference between the momentum of a photon and a proton with energy of 1 MeV.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

Similar threads

Replies
15
Views
1K
Replies
10
Views
3K
Replies
3
Views
5K
Replies
67
Views
6K
Replies
28
Views
2K
Back
Top